Two particles having mass M and m are moving in a circular path having radius R and r- If their time period are same- then the ratio of their angular velocity will be -displaystylefrac-r-R-1-displaystylefrac-R-r-sqrt-displaystylefrac-R-r-

Question

Toppr Admin · Accepted Answer

Time period of revolution -xA0- -xA0- -xA0- -xA0-T-2-x3C0-wAs according to question- -xA0- -xA0- -xA0- -xA0- -xA0- T1-T2-x2234- -xA0- -xA0- 2-x3C0-w1-2-x3C0-w2 -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-x27F9-w1-w2

Two particles having mass $M$ and $m$ are moving in a circular path having radius $R$ and $r$ . If their time period are same, then the ratio of their angular velocity will be :
$\frac{r}{R}$
$1$
$\frac{R}{r}$
$\sqrt{\frac{R}{r}}$

Time period of revolution $T = \frac{2 π}{w}$

As according to question, $T_{1} = T_{2}$

$∴$ $\frac{2 π}{w_{1}} = \frac{2 π}{w_{2}}$

$⟹ w_{1} = w_{2}$

Two particles having mass M and m are moving in a circular path having radius R and r. If their time period are same, then the ratio of their angular velocity will be :rR1Rr√Rr

Time period of revolution T=2πwAs according to question, T1=T2∴ 2πw1=2πw2 ⟹w1=w2

Two particles having mass $M$ and $m$ are moving in a circular path having radius $R$ and $r$ . If their time period are same, then the ratio of their angular velocity will be :
$\frac{r}{R}$
$1$
$\frac{R}{r}$
$\sqrt{\frac{R}{r}}$

Time period of revolution $T = \frac{2 π}{w}$

As according to question, $T_{1} = T_{2}$

$∴$ $\frac{2 π}{w_{1}} = \frac{2 π}{w_{2}}$

$⟹ w_{1} = w_{2}$