Two particles undergoing simple harmonic motion of same frequency and same amplitude cross each other at $x = \frac{A}{2}$ . Phase difference between them is
$\frac{π}{3}$
$\frac{π}{2}$
$\frac{2 π}{3}$
$\frac{π}{4}$

Question

Two particles undergoing simple harmonic motion of same frequency and same amplitude cross each other x-dfrac -A-2- Phase difference between them isdfrac -pi-3-dfrac -pi-2-dfrac -2pi-3-dfrac -pi-4-

Toppr Admin · Accepted Answer

Two particles undergoing simple harmonic motion of same frequency and same amplitude cross each other at x=A2. Phase difference between them isπ3π22π3π4

Two particles undergoing simple harmonic motion of same frequency and same amplitude cross each other at $x = \frac{A}{2}$ . Phase difference between them is
$\frac{π}{3}$
$\frac{π}{2}$
$\frac{2 π}{3}$
$\frac{π}{4}$