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- 729T
- 27T
- 3T
- T/3
- T/27

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Solution

Verified by Toppr

Kepler's third law of planetary motion gives T2∝r3

where T= time period of revolution , r= length of semi major axis of elliptical orbit

by this relation we get , TXTY=r3Xr3Y

T2XT2Y=a3(9a)3

but given TX=T

therefore T2T2Y=a3729a3

or TY=27T

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