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Correct option is C)

Let the point be at distance a from x=0.

We know that$V=4πϵ_{0}r1 $ where r is the distance from the charge and the point. The total potential will be the sum of the two potentials.

From the conditions of the problem, we have

$4πϵ_{0}a2 −4πϵ_{0}(6−a)1 =0$

here we get $a=4$

Also, there will be a point on the right side of the -1C charge where potential = 0. Let that point be at a distance b from x=0.

From the conditions of the problem, we have

$4πϵ_{0}b2 −4πϵ_{0}(b−6)1 =0$

Here we get $b=12$

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