Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes
A
F
B
169Fβ
C
916Fβ
D
34Fβ
Medium
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Solution
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Correct option is B)
F=r2KQ2β If 25% of charge of A transferred to B thenΒ qAβ=Qβ4Qβ=43Qβ and qBβ=βQ+4Qβ=4β3Qβ F1β=r2kqAβqBββ F1β=r2k(43Qβ)2β F1β=169βr2kQβ βΉF1β=169Fβ
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