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Two point charges q1 and q2 are placed at a distance 'd' apart as shown in the figure. The electric field intensity is zero at a point 'P' on the line joining them as shown. If the ratio q1q2 is (xr+dr)2. Find the value of x.
260857.png

Solution
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Here, the electric field at P is EP=0
1) Since E=dVdx, so dVPdx=0 . Thus the potential at P is maximum or minimum.
2) EP=kq2r2+kq1(r+d)2=0
q1q2=(r+dr)2

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