0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# Two point dipoles p^k and p2^k are located at (0,0,0) and (1m,0,2m). Find the field at the point (1,0,0).9p32πε0^k−7p32πε0^k7p32πε0^knone of these

A
none of these
B
7p32πε0^k
C
7p32πε0^k
D
9p32πε0^k
Solution
Verified by Toppr

#### The given point is on axis of ¯p2 dipole and at equatorial line of ¯p dipole so that field at given point is (¯E1+¯E2)¯E1=2K(p/2)23=Kp8(+^k)¯E2=Kp1(−^k)¯E1+¯E2=78Kp(−^k)=−7p32πε0^k

19
Similar Questions
Q1
Two point dipoles p^k and p2^k are located at (0,0,0) and (1m,0,2m). Find the field at the point (1,0,0).
View Solution
Q2
Two point dipoles p ^k and p2 ^k are located at (0,0,0) and (1 m,0,2 m) respectively. The resultant electric field due to the dipoles at the point (1 m,0,0) is xy×p4π ϵ0(^k). The value of xy is .
View Solution
Q3
Two point dipoles (p2) and p are located at (0,0,0) and (1m,0,2m) respectively both are parallel to x-axis resultant electric field due to the dipoles at the point (1m,0,0) is:-
View Solution
Q4
Two small electric dipoles each of dipole moment p are situated at (0,0,0) and (r,0,0). The electric potential at a point (r2,3r2,0) is
View Solution
Q5
Three points charges +q,2q and +q are placed at points (0,1,0),(0,0,0) and (1,0,0) respectively. The magnitude and direction of the resultant electric dipole moment vector of this charge assembly will be :
View Solution