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Correct option is C)

$F_{g}=r_{2}GM_{1}M_{2} $ here $F_{g}=10_{−10}$ Newton,

$m_{1}=m_{2}=1$kg,

$G=6.6×10_{−11}$

So $r_{2}=F_{g}GM_{1}M_{2} =10_{−10}6.6×10_{−11}×1×1 =0.66$

or $r=0.8125$ metre $=81.25cm=80cm$

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