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Correct option is C)

$⇒xk(4) +(1−x)k(−2) =0$

$⇒x4 =(1−x)2 $

$⇒2−2x=x$

$⇒2=3x$

$⇒x=32 $

$∴$ from the distance is $1−32 =31 $

potential is zero at $31 m$ from $−2μc.$

Hence,

option $(C)$ is correct answer.

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