Two points P and Q- diametrically opposite on a disc of radius R have linear velocities v and 2v as shown in figure- The angular speed of the disc is displaystyle frac-v-xR- Find the value of x-

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Toppr Admin · Accepted Answer

Let linear velocity of Center of Mass-COM- be u towards left- and angular speed be -x3C9- clockwise-So linear velocity of top-most point is u-x2212-x3C9-R-vand-xA0-linear velocity of bottom-most point is u-x3C9-R-2vFrom above two equations- u-3v-2 and -x3C9-v-2RSo x-2

Two points $P$ and $Q,$ diametrically opposite on a disc of radius $R$ have linear velocities $v$ and $2 v$ as shown in figure. The angular speed of the disc is $\frac{v}{x R}$ . Find the value of $x$ .

Let linear velocity of Center of Mass(COM) be $u$ towards left, and angular speed be $ω$ clockwise.
So linear velocity of top-most point is $u - ω R = v$
and, linear velocity of bottom-most point is $u + ω R = 2 v$
From above two equations, $u = 3 v / 2$ and $ω = v / 2 R$
So $x = 2$

Two points P and Q, diametrically opposite on a disc of radius R have linear velocities v and 2v as shown in figure. The angular speed of the disc is vxR. Find the value of x.

Let linear velocity of Center of Mass(COM) be u towards left, and angular speed be ω clockwise.So linear velocity of top-most point is u−ωR=vand, linear velocity of bottom-most point is u+ωR=2vFrom above two equations, u=3v/2 and ω=v/2RSo x=2

Two points $P$ and $Q,$ diametrically opposite on a disc of radius $R$ have linear velocities $v$ and $2 v$ as shown in figure. The angular speed of the disc is $\frac{v}{x R}$ . Find the value of $x$ .

Let linear velocity of Center of Mass(COM) be $u$ towards left, and angular speed be $ω$ clockwise.
So linear velocity of top-most point is $u - ω R = v$
and, linear velocity of bottom-most point is $u + ω R = 2 v$
From above two equations, $u = 3 v / 2$ and $ω = v / 2 R$
So $x = 2$