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# Two radioactive substances A and B have decay constants 5λ and λ respectively. At t=0 they have the same number of nuclei. The ratio of number of nuclei of A to those of B will be (1e)2 after a time interval14λ4λ2λ12λ

A
4λ
B
12λ
C
14λ
D
2λ
Solution
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#### The correct option is D12λDecay equation is given by N=Noe−λtWhere, λ is Decay constant; N is number of atom at time tSo, number of atom of A is given by, NA=Noe−5λtAnd that of B are given by, NB=Noe−λtTaking ration we get: NANB=e−4λtGiven that: NANB=e−2So, this will happen when, t=12λ

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