Solve

Guides

0

Question

- 4λ
- 2λ
- 12λ
- 14λ

Open in App

Solution

Verified by Toppr

Given : (No)A=(No)B=No

Using : Kt=lnNNo where, K is the decay constant⟹ Kt=lnN−lnNo

For substance A : λt=lnNA−ln(No)A

∴λt=lnNA−lnNo .............(1)

For substance B : 5λt=lnNB−ln(No)B

∴5λt=lnNB−lnNo .............(2)

Subtracting (2) from (1) we get:

λt−5λt=lnNANB

−4λt=ln1e2

−4λt=−2

⟹t=12λ

Was this answer helpful?

0