Two rational numbers between dfrac-2-3- and dfrac-5-3- are -dfrac-1-6- and dfrac-2-6-dfrac-2-3- and dfrac-4-3-dfrac-5-6- and dfrac-7-6-dfrac-1-2- and dfrac-2-1-

Changing the denominators of both numbers to 6- we get23-46-amp-53-106Numbers between the given rational numbers from the options are56-amp-76So- correct answer is option C-xA0-

Solve

Guides

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Standard IX

Mathematics

Rational Numbers

Question

Two rational numbers between $\frac{2}{3}$ and $\frac{5}{3}$ are :
$\frac{1}{6}$ and $\frac{2}{6}$
$\frac{2}{3}$ and $\frac{4}{3}$
$\frac{5}{6}$ and $\frac{7}{6}$
$\frac{1}{2}$ and $\frac{2}{1}$

\frac{1}{6}

and

\frac{2}{6}

\frac{5}{6}

and

\frac{7}{6}

\frac{2}{3}

and

\frac{4}{3}

\frac{1}{2}

and

\frac{2}{1}

Open in App

Solution

Verified by Toppr

Changing the denominators of both numbers to 6, we get
$\frac{2}{3} = \frac{4}{6} & \frac{5}{3} = \frac{10}{6}$
Numbers between the given rational numbers from the options are
$\frac{5}{6} & \frac{7}{6}$
So, correct answer is option C.

Was this answer helpful?

Similar Questions

Two rational numbers between $\frac{2}{3} a n d \frac{5}{3}$ are

(a) $\frac{1}{6} a n d \frac{2}{6}$ (b) $\frac{1}{2} a n d \frac{2}{1}$ (c) $\frac{5}{6} a n d \frac{7}{6}$ (d) $\frac{2}{3} a n d \frac{4}{3}$

View Solution

State whether the given statement is true or false:

Five rational numbers between

\frac{- 3}{2}

and

\frac{5}{3}

are

\frac{- 8}{6}, \frac{- 7}{6}, 0, \frac{1}{6}, \frac{2}{6}

View Solution

The medians for the first 7 natural numbers (1, 2, 3, 4, 5, 6, 7) and the first 6 natural numbers (1, 2, 3, 4, 5, 6) respectively are _____ .

View Solution

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

View Solution

Add using number line:

(1) 5 and 3

(2) 6 and 2

(3) (−3) and (+5)

(4) 8 and (−12)

(5) (−7) and 5

(6) 10 and (−14)

(7) (−5) and (−2)

(8) (+6) and (−9)

(9) (−4) and (−1)

(10) 1 and (−5)

View Solution

Two rational numbers between 23 and 53 are :16 and 2623 and 4356 and 7612 and 21

Changing the denominators of both numbers to 6, we get23=46&53=106Numbers between the given rational numbers from the options are56&76So, correct answer is option C.

Two rational numbers between $\frac{2}{3}$ and $\frac{5}{3}$ are :
$\frac{1}{6}$ and $\frac{2}{6}$
$\frac{2}{3}$ and $\frac{4}{3}$
$\frac{5}{6}$ and $\frac{7}{6}$
$\frac{1}{2}$ and $\frac{2}{1}$

Changing the denominators of both numbers to 6, we get
$\frac{2}{3} = \frac{4}{6} & \frac{5}{3} = \frac{10}{6}$
Numbers between the given rational numbers from the options are
$\frac{5}{6} & \frac{7}{6}$
So, correct answer is option C.