Two satellites are revolving round the earth at different heights. The ratio of their orbital speeds is $2 : 1$ . If one of them is at a height of $100 k m$ , the height of the other satellite is $($ Radius of earth $R = 6400$ km $)$

Question

Two satellites are revolving round the earth at different heights. The ratio of their orbital speeds is

2 : 1

. If one of them is at a height of

100 k m

, the height of the other satellite is

(

Radius of earth

R = 6400

km

)

Toppr Admin · Accepted Answer

Orbital velocity is given by-xA0-V-x221A-GMR-hWhere G is the Universal Gravitational constant- M is the mass of the Earth- h is the height of the satellite from the earth-apos-s surface-xA0-and R is the radius -xA0-of the earth-xA0-V-x221D-1-x221A-R-h

Two satellites are revolving round the earth at different heights. The ratio of their orbital speeds is $2 : 1$ . If one of them is at a height of $100 k m$ , the height of the other satellite is $($ Radius of earth $R = 6400$ km $)$
19600 km
29600 km
24600 km
14600 km

Orbital velocity is given by:
$V = \sqrt{\frac{G M}{R + h}}$
Where $G$ is the Universal Gravitational constant, $M$ is the mass of the Earth, $h$ is the height of the satellite from the earth's surface and $R$ is the radius of the earth.
$V \propto \frac{1}{\sqrt{R + h}}$

Two satellites are revolving round the earth at different heights. The ratio of their orbital speeds is 2:1. If one of them is at a height of 100km, the height of the other satellite is (Radius of earth R=6400 km )19600 km29600 km24600 km14600 km

Orbital velocity is given by: V=√GMR+hWhere G is the Universal Gravitational constant, M is the mass of the Earth, h is the height of the satellite from the earth's surface and R is the radius of the earth. V∝1√R+h

Two satellites are revolving round the earth at different heights. The ratio of their orbital speeds is $2 : 1$ . If one of them is at a height of $100 k m$ , the height of the other satellite is $($ Radius of earth $R = 6400$ km $)$
19600 km
29600 km
24600 km
14600 km

Orbital velocity is given by:
$V = \sqrt{\frac{G M}{R + h}}$
Where $G$ is the Universal Gravitational constant, $M$ is the mass of the Earth, $h$ is the height of the satellite from the earth's surface and $R$ is the radius of the earth.
$V \propto \frac{1}{\sqrt{R + h}}$