Two satellites of masses $m_{1}$ and $m_{2}$ ( $m_{1}$ > $m_{2}$ ) are revolving round the earth in circular orbits of radii $r_{1}$ and $r_{2}$ ( $r_{1}$ > $r_{2}$ ) respectively. Which of the following statements is true regarding their speeds $v_{1}$ and $v_{2}$ $v_{1}$ ?

Question

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Answer 1

consider a satellite revolving at a distance r from the earth.
inward force is $\frac{G M m}{r ^{2}}$
and outward force is $\frac{m v ^{2}}{r}$
equating both the expression for equilibrium.
so $v = \frac{G M}{r}$ .
so to if $r$ increses then $v$ decrease.
so best possible answer is option C.

Answer 2

consider a satellite revolving at a distance r from the earth.

inward force is

\frac{G M m}{r ^{2}}

and outward force is

\frac{m v ^{2}}{r}

equating both the expression for equilibrium.

so

v = \frac{G M}{r}

.

so to if

r

increses then

v

decrease.

so best possible answer is option C.

List - I	List - II
P. $\frac{v _{1}}{v _{2}}$	1. $\frac{1}{8}$
Q. $\frac{L _{1}}{L _{2}}$	2. $1$
R. $\frac{K _{1}}{K _{2}}$	3. $2$
S. $\frac{T _{1}}{T _{2}}$	4. $8$

Two satellites of masses $m_{1}$ and $m_{2}$ ( $m_{1}$ > $m_{2}$ ) are revolving round the earth in circular orbits of radii $r_{1}$ and $r_{2}$ ( $r_{1}$ > $r_{2}$ ) respectively. Which of the following statements is true regarding their speeds $v_{1}$ and $v_{2}$ $v_{1}$ ?

$v_{1}$ = $v_{2}$

$v_{1}$ $>$ $v_{2}$

$v_{1}$ $<$ $v_{2}$

$\frac{v _{1}}{r _{1}} = \frac{v _{2}}{r _{2}}$

consider a satellite revolving at a distance r from the earth.
inward force is $\frac{G M m}{r ^{2}}$
and outward force is $\frac{m v ^{2}}{r}$
equating both the expression for equilibrium.
so $v = \frac{G M}{r}$ .
so to if $r$ increses then $v$ decrease.
so best possible answer is option C.

A satellite of mass 'm' is revolving in circular orbit of radius 'r' round the earth. Its angular momentum w.r.t. the centre of its orbit is ( $M =$ mass of earth, $G =$ universal gravitational constant)

Two satellites $A$ and $B$ are moving round the earth in a circular orbit in the equatorial plane. Satellite $A$ is moving (or rotating) in the eastward direction while $B$ is moving westward. An observer earth measures the time period $T_{A}$ and $T_{B}$ of $A$ and $B$ and finds that:

Two satellites of mass $m$ and $2 m$ are revolving in two circular orbits of radii $r$ and $2 r$ around an imaginary planet, on the surface of with gravitational force is inversely proportional to distance from its centre. The ratio of orbital speed of satellite is :

Revise with Concepts

Escape Speed

Earth Satellites

Orbital Velocity

Geostationary Satellite - Medium

Energy of an Orbiting Satellite

Geostationary and Polar Satellites

Two satellites of masses m1​ and m2​(m1​> m2​) are revolving round the earth in circular orbits of radii r1​ and r2​(r1​> r2​) respectively. Which of the following statements is true regarding their speeds v1​ and v2​v1​?

v1​ = v2​

v1​ > v2​

v1​ < v2​

r1​v1​​=r2​v2​​

consider a satellite revolving at a distance r from the earth.inward force is r2GMm​and outward force is rmv2​equating both the expression for equilibrium.so v=rGM​​.so to if r increses then v decrease.so best possible answer is option C.

A satellite of mass 'm' is revolving in circular orbit of radius 'r' round the earth. Its angular momentum w.r.t. the centre of its orbit is (M= mass of earth, G= universal gravitational constant)

Two satellites A and B are moving round the earth in a circular orbit in the equatorial plane. Satellite A is moving (or rotating) in the eastward direction while B is moving westward. An observer earth measures the time period TA​ and TB​ of A and B and finds that:

Two satellites of mass m and 2m are revolving in two circular orbits of radii r and 2r around an imaginary planet, on the surface of with gravitational force is inversely proportional to distance from its centre. The ratio of orbital speed of satellite is :

Revise with Concepts

Escape Speed

Earth Satellites

Orbital Velocity

Geostationary Satellite - Medium

Energy of an Orbiting Satellite

Geostationary and Polar Satellites

Two satellites of masses $m_{1}$ and $m_{2}$ ( $m_{1}$ > $m_{2}$ ) are revolving round the earth in circular orbits of radii $r_{1}$ and $r_{2}$ ( $r_{1}$ > $r_{2}$ ) respectively. Which of the following statements is true regarding their speeds $v_{1}$ and $v_{2}$ $v_{1}$ ?

$v_{1}$ = $v_{2}$

$v_{1}$ $>$ $v_{2}$

$v_{1}$ $<$ $v_{2}$

$\frac{v _{1}}{r _{1}} = \frac{v _{2}}{r _{2}}$

consider a satellite revolving at a distance r from the earth.
inward force is $\frac{G M m}{r ^{2}}$
and outward force is $\frac{m v ^{2}}{r}$
equating both the expression for equilibrium.
so $v = \frac{G M}{r}$ .
so to if $r$ increses then $v$ decrease.
so best possible answer is option C.

A satellite of mass 'm' is revolving in circular orbit of radius 'r' round the earth. Its angular momentum w.r.t. the centre of its orbit is ( $M =$ mass of earth, $G =$ universal gravitational constant)

Two satellites $A$ and $B$ are moving round the earth in a circular orbit in the equatorial plane. Satellite $A$ is moving (or rotating) in the eastward direction while $B$ is moving westward. An observer earth measures the time period $T_{A}$ and $T_{B}$ of $A$ and $B$ and finds that:

Two satellites of mass $m$ and $2 m$ are revolving in two circular orbits of radii $r$ and $2 r$ around an imaginary planet, on the surface of with gravitational force is inversely proportional to distance from its centre. The ratio of orbital speed of satellite is :