Two short bar magnets of magnetic moments 0.125Am2 and 0.512Am2 are placed with their like poles facing each other. If the distance between the centres of the magnet is 0.26m. The distance of neutral point from the weaker magnet is
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Baxial=μ02M4πr3 Equating the magnetic fields due to the two bar magnets, M1x3=M2(d−x)3 Solving the above for x (distance from the center of weaker magnet to the neutral point), gives the formula in the hint. Putting in the values, we get, x=0.1m
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Disclaimer: No option as 0.08dyne was given in the original paper.
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