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Question
Two simple harmonic motions are given by
$y_{1}=asin[(2π )t+ϕ]$
and
$y_{2}=bsin[(32π )t+ϕ]$
. The phase difference between these after 1 s is:
A
zero
B
$π/2$
C
$π/4$
D
$π/6$
Medium
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Solution
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Correct option is D)
At t = 1 s
$ϕ_{1}=2π +ϕ$
and
$ϕ_{2}=32π +ϕ$
$∴$
$Δϕ=ϕ_{2}−ϕ_{1}=6π $
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