Two spheres- of radius 8 and 2- are resting on a plane table so that they touch each other- How far apart are their points of contact with the plane table top-6878sqrt-2-9

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Toppr Admin · Accepted Answer

The distance between centers is 8-2-10the vertical distance is 8-x2212-2-6Let the horizontal distance be hWe have h2-102-x2212-62-100-x2212-36-64 - which implies h-8

Two spheres, of radius 8 and 2, are resting on a plane table top so that they touch each other. How far apart are their points of contact with the plane table top?
6
8
7
$8 \sqrt{2}$
9

The distance between centers is $8 + 2 = 10$
the vertical distance is $8 - 2 = 6$
Let the horizontal distance be $h$
We have $h^{2} = 10^{2} - 6^{2} = 100 - 36 = 64$ , which implies $h = 8$

Two spheres, of radius 8 and 2, are resting on a plane table top so that they touch each other. How far apart are their points of contact with the plane table top?6878√29

The distance between centers is 8+2=10the vertical distance is 8−2=6Let the horizontal distance be hWe have h2=102−62=100−36=64 , which implies h=8

Two spheres, of radius 8 and 2, are resting on a plane table top so that they touch each other. How far apart are their points of contact with the plane table top?
6
8
7
$8 \sqrt{2}$
9

The distance between centers is $8 + 2 = 10$
the vertical distance is $8 - 2 = 6$
Let the horizontal distance be $h$
We have $h^{2} = 10^{2} - 6^{2} = 100 - 36 = 64$ , which implies $h = 8$