From Coulomb's law, force between them F=KQ2r2 ....(1)
Step 2: Distribution of charges
When an identical uncharged spherical conductor A is brought in contact with charged sphere B.
By symmetry, the total charge will be shared equally among them, as both have equal radii.
∴ Charge on A and B =Q2
Now, when the conductor A is brought in contact with C.
They will also share equal charge among themselves, as both have equal radii.
∴ Charge on A and C =Q+Q22=3Q4
Step 3: Calculation of new force
New coulomb force between B and C:
F′=KQ2×3Q4r2=38KQ2r2
From equation (1), we get: F′=38F
Hence, Option D is correct