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- F4
- 3F4
- F8
- 3F8

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Solution

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Step 1: Calculation of initial force

Let B and C have charge Q each initially and are seperated by r distance.

From Coulomb's law, force between them F=KQ2r2 ....(1)

Step 2: Distribution of charges

When an identical uncharged spherical conductor A is brought in contact with charged sphere B.

By symmetry, the total charge will be shared equally among them, as both have equal radii.

∴ Charge on A and B =Q2

Now, when the conductor A is brought in contact with C.

They will also share equal charge among themselves, as both have equal radii.

∴ Charge on A and C =Q+Q22=3Q4

Step 3: Calculation of new force

New coulomb force between B and C:

F′=KQ2×3Q4r2=38KQ2r2

From equation (1), we get: F′=38F

Hence, Option D is correct

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