Two trains, each of length $125 m e t r e$ , are running in parallel tracks in opposite directions. One trains is running at a speed $65 k m / h o u r$ and they cross each other in $6$ seconds. The speed of the other train is:

Question

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Answer 1

Let speed of second
train = x km/hr
time = $\frac{l _{1} + l _{2}}{R e l a t i v e s p e e d i n o p p . d i r e c t i o n .}$
$6 = \frac{1 2 5 + 1 2 5}{( 6 5 + x ) \frac{5}{1 8}}$
$6 = \frac{( 2 5 0 \times 1 8 )}{( 6 5 + x ) 5}$
$65 + x = 50 \times 3$
x = 150 - 65
x = 85 km / hr.

Answer 2

Let speed of second

train = x km/hr

time =

\frac{l _{1} + l _{2}}{R e l a t i v e s p e e d i n o p p . d i r e c t i o n .}

6 = \frac{1 2 5 + 1 2 5}{( 6 5 + x ) \frac{5}{1 8}}

6 = \frac{( 2 5 0 \times 1 8 )}{( 6 5 + x ) 5}

65 + x = 50 \times 3

x = 150 - 65

x = 85 km / hr.