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Question

Two uniform dice marked 1 to 6 are thrown together. The probability that the score on the two dice is at least seven is
  1. 512
  2. 712
  3. 12
  4. 34

A
34
B
512
C
712
D
12
Solution
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Probability that the score on the two dice is at least seven= 1 Probability when score on the two dice is less than seven.

There are following cases when score on the two dice is less than seven:

When sum is 2:(1,1);3:(1,2)(2,1);4:(1,3)(2,2)(3,1);5:(1,4)(2,3)(3,2)(4,1);6:(1,5)(2,4)(3,3)(4,2)(5,1) =15 cases.

Probability that the score on the two dice is at least seven=1156×6=712

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