Ultrasonic signal sent from SONAR returns to it after reflection from a rock after a lapse of 1- s- If the velocity of ultrasound in water is 1600- m-s- the depth of the rock in water is 300- m400- m500- m800- m

Question

Toppr Admin · Accepted Answer

If d is the distance of rock from SONAR then-The distance covered by the sound wave is-2d-vt-x21D2-d-v-xD7-t2-1600-xD7-12-800-xA0-m

Ultrasonic signal sent from $S O N A R$ returns to it after reflection from a rock after a lapse of $1 s$ . If the velocity of ultrasound in water is $1600 m / s$ , the depth of the rock in water is
$300 m$
$400 m$
$500 m$
$800 m$

If $d$ is the distance of rock from SONAR then,

The distance covered by the sound wave is:
$2 d = v t$

$\Rightarrow d = \frac{v \times t}{2}$

$= \frac{1600 \times 1}{2} = 800 m$

Ultrasonic signal sent from SONAR returns to it after reflection from a rock after a lapse of 1s. If the velocity of ultrasound in water is 1600m/s, the depth of the rock in water is 300m400m500m800m

If d is the distance of rock from SONAR then,The distance covered by the sound wave is:2d=vt⇒d=v×t2=1600×12=800 m

Ultrasonic signal sent from $S O N A R$ returns to it after reflection from a rock after a lapse of $1 s$ . If the velocity of ultrasound in water is $1600 m / s$ , the depth of the rock in water is
$300 m$
$400 m$
$500 m$
$800 m$

If $d$ is the distance of rock from SONAR then,

The distance covered by the sound wave is:
$2 d = v t$

$\Rightarrow d = \frac{v \times t}{2}$

$= \frac{1600 \times 1}{2} = 800 m$