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Question

- h=1c(λ2−λ1)(E1−E2)
- h=(E1+E2)λ1λ2c(λ2+λ1)
- h=(E1−E2)λ1λ2c(λ2−λ1)
- h=1c(λ2+λ1)(E1+E2)

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Solution

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According to the question:

hν1−E0=E1

hν2−E0=E2 , where, E0 is the ionization energy of the hydrogen.

Solving this two equation we will get:

h=(E1−E2)λ1λ2c(λ2−λ1).

So, the answer is option (C).

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