Question

Uncertainty in position of a hypothetical subatomic particle is 1 $A^o$ and uncertainty in velocity is $\frac{3.3}{4\pi }\times {10}^5$ m/s. Then the mass of the particle is approximately: $[h=6.6\times {10}^{-34}Js]$

• A. $4\times {10}^{-29}$kg
• B. $2\times {10}^{-27}$kg
• C. $2\times {10}^{-29}$kg
• D. $2\times {10}^{-28}$kg

Answer 1

Answer: (C)

$m=\frac{h}{4\pi \Delta V\Delta X}=\frac{6.6\times {10}^{-34}}{4\times \pi \times 1\times {10}^{-10}\times \frac{3.3}{4\pi }\times {10}^5}=2\times {10}^{-29}kg$