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Standard XI
Mathematics
NCERT
Question
Using Binomial Theorem, evaluate
(
101
)
4
Open in App
Solution
Verified by Toppr
(
101
)
4
=
(
100
+
1
)
4
=
4
C
0
(
100
)
4
+
4
C
1
(
100
)
3
(
1
)
+
4
C
2
(
100
)
2
(
1
)
2
+
4
C
3
(
100
)
(
1
)
3
+
4
C
4
(
1
)
4
=
(
100
)
4
+
4
(
100
)
3
+
6
(
100
)
2
+
4
(
100
)
+
(
1
)
4
=
100000000
+
4000000
+
60000
+
400
+
1
=
104060401
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