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Question

Using dimensions, show that 1 newton=105 dyne

Solution
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Let 1 newton =n dynes

n=M1L1t12M2L2t22=M1M2×L1L2×t12t22

=Rggm×mcm×(ss)2

=103gmgm×102cmcm×s0

=103102=105

1newton=105dyne.
Hence,
we get,
1newton=105dyne.

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