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Question

Using identities, evaluate:
712.
  1. 5041
  2. 3041
  3. 6041
  4. 2041

A
2041
B
6041
C
3041
D
5041
Solution
Verified by Toppr

Given, 712,
i.e. 712 =(70+1)2.

We know,
(x+y)2=x2+y2+2xy.

Then,
712=(70+1)2=702+(2×70×1)+12=4900+140+1=5040+1=5041.

Hence, 712=5041.

Therefore, option A is correct.

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