Using ruler and compass only- construct the quadrilateral ABCD- having given AB - 5 cm- BC - 2-5 cm- CD - 6 cm- angle BAD - 90-circ- and the diagonal AC - 5-5 cm-

Question

Toppr Admin · Accepted Answer

Steps -i- draw AB - 5 cm-ii- Now draw-160-angle XAB- such that it is -90-circ-iii- taking A and B as a ceentre and radus 2-5 cm and 5-5 cm draw arcs cuts off at C-iv- Now join BC and AC-v- Taking C as a centre and radius 6 cm draw arcs at D on AX-ABCD is the required quadriateral-

Using ruler and compass only, construct the quadrilateral ABCD, having given AB = $$5$$ cm, BC = $$2.5$$ cm, CD = $$6$$ cm, angle BAD = $$90^{\circ}$$ and the diagonal AC = $$5.5$$ cm.

Steps :
(i) draw AB = 5 cm.
(ii) Now draw $$\angle XAB$$ such that it is $$90^{\circ}$$.
(iii) taking A and B as a ceentre and radus 2.5 cm and 5.5 cm draw arcs cuts off at C.
(iv) Now join BC and AC.
(v) Taking C as a centre and radius 6 cm draw arcs at D on AX.
ABCD is the required quadriateral.

Using ruler and compass only, construct the quadrilateral ABCD, having given AB = $$5$$ cm, BC = $$2.5$$ cm, CD = $$6$$ cm, angle BAD = $$90^{\circ}$$ and the diagonal AC = $$5.5$$ cm.

Steps :(i) draw AB = 5 cm.(ii) Now draw $$\angle XAB$$ such that it is $$90^{\circ}$$.(iii) taking A and B as a ceentre and radus 2.5 cm and 5.5 cm draw arcs cuts off at C.(iv) Now join BC and AC.(v) Taking C as a centre and radius 6 cm draw arcs at D on AX.ABCD is the required quadriateral.

Steps :
(i) draw AB = 5 cm.
(ii) Now draw $$\angle XAB$$ such that it is $$90^{\circ}$$.
(iii) taking A and B as a ceentre and radus 2.5 cm and 5.5 cm draw arcs cuts off at C.
(iv) Now join BC and AC.
(v) Taking C as a centre and radius 6 cm draw arcs at D on AX.
ABCD is the required quadriateral.