Using the dimensional method derive the relation between the units of force in the SI and CGS system.
Let 1 newton(SI) = x dyne(CGS)
Dimensions of forces are [L1M1T−2]
∴[L11M11T−21]=x[L12M12T−22]
∴x=(L1L2)1(M1M2)1(T1T2)−2
=(mcm)1(kgg)1(ss)−2
=102×103=105
∴1newton=105dyne