Using the equation of state pV-nRT- show that- a given temperature the density of a gas is proportional to its gas pressure p-

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Toppr Admin · Accepted Answer

PV-nRT-wMRTHence- PM-wVRT-x3C1-RT-x3C1-x221D-PHere- -x3C1-wVn-wM-x3C1- is the density- P is the pressure- V is the volume- n is the number of moles- R is the ideal gas constant- T is the temperature and M is the molar mass-

Using the equation of state $p V = n R T$ , show that, at a given temperature the density of a gas is proportional to its gas pressure $p$ .

$P V = n R T = \frac{w}{M} R T$
Hence, $P M = \frac{w}{V} R T = ρ R T$
$ρ \propto P$
Here, $ρ = \frac{w}{V}$
$n = \frac{w}{M}$
$ρ$ is the density, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature and M is the molar mass.

Using the equation of state pV=nRT, show that, at a given temperature the density of a gas is proportional to its gas pressure p.

PV=nRT=wMRTHence, PM=wVRT=ρRTρ∝PHere, ρ=wVn=wMρ is the density, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature and M is the molar mass.

Using the equation of state $p V = n R T$ , show that, at a given temperature the density of a gas is proportional to its gas pressure $p$ .

$P V = n R T = \frac{w}{M} R T$
Hence, $P M = \frac{w}{V} R T = ρ R T$
$ρ \propto P$
Here, $ρ = \frac{w}{V}$
$n = \frac{w}{M}$
$ρ$ is the density, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature and M is the molar mass.