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Question

Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:
(i) Fe3+(aq) and I(aq)
(ii) Ag+(aq) and Cu(s)
(iii) Fe3+(aq) and Br(aq)
(iv) Ag(s) and Fe3+(aq)
(v) Br2(aq) and Fe2+(aq)

Solution
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(i) When emf is positive, the reaction is feasible.
Eocell=EoFeE0I2=0.770.54=0.23V
Reaction is feasible.

(ii) Eocell=EoAgEoCu=0.800.34=0.46V
Reaction is feasible.

(iii) Eocell=EoFeE0Br2=0.771.09=0.32 V
Reaction is not feasible.

(iv) Eocell=EoFeE0Ag=0.770.80=0.03 V
Reaction is not feasible.

(v) Eocell=EoBr2E0Fe=1.090.77=0.32 V
Reaction is feasible.

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Q1
Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:
(i) Fe3+(aq) and I(aq)
(ii) Ag+(aq) and Cu(s)
(iii) Fe3+(aq) and Br(aq)
(iv) Ag(s) and Fe3+(aq)
(v) Br2(aq) and Fe2+(aq)
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Q2

Using the standard electrode potentials given in the Table 8.1, predict if the reaction between the following is feasible:

(a) Fe3+(aq) and I(aq)

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Q3

Using the standard electrode potential valuesl predict if the reaction between the following is feasible :

(i) Fe3+(aq) and I(aq)

(ii) Ag+(aq) and Cu(s)

(iii) Fe3+(aq) and Br(aq)

(iv) Ag(s) and Fe3+(aq)

(v) Br2(aq) and Fe2+(aq)

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E12t21=+0.541VE(Cu2+Cu)=+0.34VE(12Br2Br)=+1.09VE(Ag+Ag)=+0.80VE(Fe3+Fe2+)=+0.77V

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