Using varepsilon - - displaystyle frac-dphi-dt- and varepsilon - iR the current in the loop after the external field has stopped changing-displaystyle frac-di-dt- - - left- frac-2R-mu-0 pi a- right - idisplaystyle frac-di-dt- - - frac-R-mu-0 a- idisplaystyle frac-di-dt- - frac-2R-mu-0 a- idisplaystyle frac-di-dt- - frac-2R-3 mu-0 pi a- i

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Toppr Admin · Accepted Answer

-x3B5-x2212-d-x3D5-dt-x2212-x3BC-0-x3C0-a2didt-iRor didt-x2212-2R-x3BC-0-x3C0-a-i

Using ε=−dϕdt and ε=iR find the current in the loop after the external field has stopped changing.didt=−(2Rμ0πa)ididt=−Rμ0aididt=−2Rμ0aididt=−2R3μ0πai

ε=−dϕdt=−μ0πa2didt=iRor didt=−(2Rμ0πa)i

$ε = \frac{- d ϕ}{d t}$

$= \frac{- μ_{0} π a}{2} \frac{d i}{d t} = i R$

or $\frac{d i}{d t} = - (\frac{2 R}{μ_{0} π a}) i$