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Question

V0 is the potential at the origin in an electric field. E=ExiEyj. The potential at the point (x,y) is:


  1. V0xEx+yEy
  2. V0+xEx+yEy
  3. x2+y2E2x+E2yV0
  4. xEx+yEyV0

A
x2+y2E2x+E2yV0
B
V0xEx+yEy
C
V0+xEx+yEy
D
xEx+yEyV0
Solution
Verified by Toppr

We know
V(x1)V(x2)=x2x1Edx.
Now potential change in x direction
Vx(x)Vx(o)=oxExdx=Exx.
Vx(x)=Vx(o)Exx
Potential change in y direction
Vy(y)Vy(o)=oy(Ey)dy=+Eyy
Vy(y)=Vy(o)+Eyy
Now total potential at (x,y)
=Vx+Vy
=Vx(o)Exx+Vy(o)+Eyy
=VoxEx+yEy

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