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Variation of G Due to the Rotation of Earth

Question

Value of g is:

maximum at poles
maximum at equator
minimum at poles
same everywhere

A

maximum at equator

B

same everywhere

C

maximum at poles

D

minimum at poles

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Solution

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The correct option is A maximum at poles
The expression for acceleration due to gravity is given by $g = \frac{G M}{R^{2}}$
as we know the radius of the earth at poles is minimum, so acceleration due to gravity will be maximum at poles because g is inversely proportional to $R^{2}$ .
also, the net acceleration due to gravity is affected (decreases) by centrifugal force due to rotation of the earth.
poles are less affected by rotation also their radius is small so poles have maximum value of g.
so the best option is A.

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