0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Velocity and acceleration vectors of a charged particle moving in a magnetic field at some instant are →v=3^i+4^j and →a=2^i+x^j. Select the correct alternative(s) :x=1.5x=3kinetic energy of the particle is constantmagnetic field is along z-direction

A
x=1.5
B
x=3
C
kinetic energy of the particle is constant
D
magnetic field is along z-direction
Solution
Verified by Toppr

Force & velocity are perpendicular to each other in magnetic fieldSo→V⋅→a=0(3^i+4^j)⋅(2^i+x^j)=06+4x=0x=−1.5No work is done by magnetic field. So, KE of particle is constant

0
Similar Questions
Q1
Velocity and acceleration vectors of a charged particle moving in a magnetic field at some instant are v=3^i+4^j and a=2^i+x^j. Select the correct alternative(s) :
View Solution
Q2
Velocity and acceleration vectors of a charged particle moving in a magnetic field at some instant are v=3^i+4^j and a=2^i+x^j (Select the correct alternative(s).
View Solution
Q3
Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are v=3^i+4^j and a=2^i+x^j. Select the correct options.
View Solution
Q4
Velocity and acceleration vectors of charged particle moving perpendicular to the direction of a magnetic field at a given instant of time are v=2^i+c^j and a=3^i+4^j respectively. Then the value of 'c' is:
View Solution
Q5
A charged particle of charge q and mass m is moving with velocity v (as shown in the figure) in a uniform magnetic field B along negative z – direction. Select the correct alternative(s).

View Solution