Question

# Velocity and acceleration vectors of a charged particle moving in a magnetic field at some instant are →v=3^i+4^j and →a=2^i+x^j. Select the correct alternative(s) :

A
x=1.5
B
x=3
C
magnetic field is along z-direction
D
kinetic energy of the particle is constant
Solution
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#### Force & velocity are perpendicular to each other in magnetic fieldSo→V⋅→a=0(3^i+4^j)⋅(2^i+x^j)=06+4x=0x=−1.5No work is done by magnetic field. So, KE of particle is constant

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