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Updated on : 2022-09-05

Solution

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Correct option is A)

The particle will travel in a parabolic trajectory OA.

Let the time to reach A is $t_{0}$.

$a_{y}=−mqE $

x-coordinate of the point A is $x=(2vcosθ)t_{0}$

$∴qE3 mv_{2} =(2vcosθ)t_{0}=(2vcos60_{∘})t_{0}=vt_{0}$

$⇒t_{0}=vqE3 mv_{2} =qE3 mv $

$v_{y}=u_{y}+a_{y}t_{0}=2vsin60_{∘}+a_{y}t_{0}=2v23 −mqE qE3 mv =3 v−3 v=0$

At point A, the particle velocity is purely along the x-axis and is $2vcos60_{∘}=v$

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