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VESTION 4 po In m-RNA base sequence is 5' - UCU ACA GUG AUC GUG ACC_3'. What is the possible number of codons if the genetic codon is considered non-overlapping and overlapping respectively? 1. 5 & 17 26 & 16 3. 5 & 16 4. 6 & 18

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Q1

Match the following:

A. Feature of the genetic code: (1 Mark)	1. Amino acids
B. The start codon is: (1 Mark)	2. Unambiguous
C. The triplet codons code for: (1 Mark)	3. AUG
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Q2

Consider the following sequence on mRNA, AUGGCAGUGCCA. Assuming that genetic code is overlap then how many number of codon may be present on this genetic code?

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Q3

In genetic coding, triplet codons make possible 64 types of codons. If the genetic code was a doublet instead of a triplet codon, the number of types of codons possible would be

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Q4

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DNA template strand:

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Q5

what does the statement " Codons are commaless and do not exhibit overlapping" imply?

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