Volume of a gas t-oC is 20 litre when temperature of gas increases by 50-oC constant pressure than volume of gas increased by 25- than calculate value of it-

Given- V1-20LT1-toCV2-25100-xD7-20-V1-xA0- -xA0- -xA0- -5L-20L-25LT2-t-50V-x221D-T-x21D2-V1T1-V2T2-x21D2-20t-25t-50-x21D2-4-t-50-5t-x21D2-200oC-t

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Standard XII

Chemistry

Charles' Law

Question

Volume of a gas at $t^{o}$ C is $20$ litre when temperature of gas increases by $50^{o}$ C at constant pressure than volume of gas increased by $25 %$ than calculate value of it?

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Solution

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Given: $V_{1} = 20 L$
$T_{1} = t^{o} C$
$V_{2} = (\frac{25}{100} \times 20) + V_{1}$
$= 5 L + 20 L = 25 L$
$T_{2} = t + 50$

$V \propto T$
$\Rightarrow \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\Rightarrow \frac{20}{t} = \frac{25}{t + 50}$
$\Rightarrow 4 (t + 50) = 5 t$
$\Rightarrow 200^{o} C = t$

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