Question

List 1The magnitude of average velocity from $t=0$ to $t=t_{1}$Magnitude of acceleration at $t=t_{1}$Magnitude of acceleration at $t=t_{0}$Speed at $t_{1}$

List 2Same for $A$, $B$ and $C$Maximum for $A$Minimum for $C$Maximum for $C$

Open in App

Updated on : 2022-09-05

Solution

Verified by Toppr

R.E.F imageΒ

A) By definition : Avg. velocity = $totaltimetakentotaldisplacementβ$

AS $V=dtdxβββ³x=β«x.dt$

So to find displacement, see the area under the from graph:

$β$ (Area under A)$<$ (Area under B)$<$ (Area under C)

$β(β³x)_{A}<(β³x)_{B}<(β³x)_{C}$

$β(Avg.vel)_{A}<(Avg.vel)_{B}<(Avg.vel)_{C}βAns:4β$

B) REF.Image.

For acceleration check the

slope of v-t graph as

$a=dtdvβ$

At $t=t_{1}:m_{A}>m_{B}>M_{C}$

$βa_{A}>a_{B}>a_{C}$Β

$Ans:2,3β$

C) REF. Image.

At $t=0:m_{C}>m_{B}>m_{A}$

$βa_{C}>a_{B}>a_{A}$

$Ans:4β$

(D) Speed $β‘$ Magnitude of velocity.

as velocity for all 3 answer has same value

$t=t_{1}βAns:1β$

Solve any question of Motion in a Straight Line with:-

Was this answer helpful?

0

0