Water is poured into a vessel a constant rate phi m - - 3 - - s- There is a small aperture of the cross-sectional area an the bottom of the vessel- The maximum level of water in the vessel is proportional to -phiphi - - 2 -1 - a1 - a - - 2 -

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Toppr Admin · Accepted Answer

-xA0-mass emerging-xA0-m-avm-a-x221A-2ghmaxhmax-m2a2-2g-xA0-hmax-x221D-1a2-xA0-Answer-D-xA0-

Water is poured into a vessel at a constant rate $ϕ m^{3} / s$ . There is a small aperture of the cross-sectional area an at the bottom of the vessel. The maximum level of water in the vessel is proportional to :
$ϕ$
$ϕ^{2}$
$1 / a$
$1 / a^{2}$

$mass emerging.$
$m = a v$
$m = a \sqrt{2 g h_{max}}$
$h_{m a x} = \frac{m^{2}}{a^{2} (2 g)}$
$h_{m a x} \propto \frac{1}{a^{2}}$
$Answer:-(D)$

Water is poured into a vessel at a constant rate ϕm3/s. There is a small aperture of the cross-sectional area an at the bottom of the vessel. The maximum level of water in the vessel is proportional to :ϕϕ21/a1/a2

mass emerging. m=avm=a√2ghmaxhmax=m2a2(2g) hmax∝1a2 Answer:-(D)

Water is poured into a vessel at a constant rate $ϕ m^{3} / s$ . There is a small aperture of the cross-sectional area an at the bottom of the vessel. The maximum level of water in the vessel is proportional to :
$ϕ$
$ϕ^{2}$
$1 / a$
$1 / a^{2}$

$mass emerging.$
$m = a v$
$m = a \sqrt{2 g h_{max}}$
$h_{m a x} = \frac{m^{2}}{a^{2} (2 g)}$
$h_{m a x} \propto \frac{1}{a^{2}}$
$Answer:-(D)$