The correct option is C n2
Maximum resistance can be obtained when the resistance are connected in series and minimum resistance can be obtained when the resistances are connected in parallel.
Rseries=R+R+R+...=nR.
Rparallel=1R+1R+1R+...=Rn.
Therefore, RseriesRparallel=nRRn=n2.
Hence, he ratio of the maximum to minimum resistance that can be obtained by combining them is n2.