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Question

What are the products when ethyl isopropyl ether is cleaved with concentrated $H I$ ?
Ethanol and 2-iodo-2-methyl propane
Ethanol and 2-methyl propane
Iodoethane and isopropyl alcohol
Iodoethane and 2-methyl propane

A

Ethanol and 2-iodo-2-methyl propane

B

Iodoethane and isopropyl alcohol

C

Iodoethane and 2-methyl propane

D

Ethanol and 2-methyl propane

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Solution

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The reaction of ethyl isopropyl ether with concentrated hydroiodic acid gives iodoethane and isopropyl alcohol.

In this reaction, lower alkyl halide and higher alcohol are obtained.

Option C is correct.

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