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Question

What are the value of $a$ and $b$ respectively in the reaction $_{9}^{4} B e +_{2}^{4} H e \to_{b}^{a} X +_{0}^{1} n$
$17, 7$
$7, 11$
$12, 6$
$6, 12$

A

12, 6

B

6, 12

C

17, 7

D

7, 11

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Solution

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$_{9}^{4} B e +_{2}^{4} H e ⟶_{b}^{a} X +_{0}^{1} n$
or, $_{9}^{4} B e +_{2}^{4} H e ⟶_{11}^{7} X +_{0}^{1} n$
$a = 7$
$b = 11$ .

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