Question

a) the resistance of the appliance, and b) the safe limit of current in it, while in use?

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Solution

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$Power Rating of an Electrical Appliance:$

$∙$ Every electrical appliance has a power rating which tells how much electricity it needs to work. This is usually given in watts (W) or kilowatts (kW) (1000W = 1kW).

$∙$ Power rating is also accompanied by the maximum working voltage, an appliance needs to work with its full capacity.

$Calculation of Resistance of an Electrical Appliance:$

$∙$ The relationship between Power Rating, Working Voltage and Resistance of an electrical appliance is $P=RV_{2} $.

$∴$ $R=PV_{2} $

$Calculation of Safe Limit of Current:$

As we know, $P=VI$,

$∴$ $I=VP $

$∙$ This current is the safe limit of an electrical appliance, if it is operated across maximum operating voltage $V$.

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