What is the change in oxidation number of carbon in the following reaction?
$C H_{4} (g) + 4 C l_{2} (g) \to C C l_{4} (l) + 4 H C l (g)$

Question

What is the change in oxidation number of carbon in the following reaction-CH-4 -g- - 4Cl-2 -g-longrightarrow CCl-4 -l- - 4HCl-g-

Toppr Admin · Accepted Answer

Correct option is B- -4- to - 4-overset -4- CH-4 -g- - 4Cl-2 -g-longrightarrow -overset -4- CCl-4 -l- - 4HCl-g-The oxidation state of -H- and -Cl- are -1 and -1 respectively- Therefore the oxidation state of C in methane is -4- and that in carbon tetrachloride is -4-

What is the change in oxidation number of carbon in the following reaction?
$$CH_4 (g) + 4Cl_2 (g)\longrightarrow CCl_4 (l) + 4HCl(g)$$

Correct option is B. $$-4$$ to $$+ 4$$
$$\overset {-4} CH_4 (g) + 4Cl_2 (g)\longrightarrow \overset {+4} CCl_4 (l) + 4HCl(g)$$
The oxidation state of $$H$$ and $$Cl$$ are +1 and -1 respectively. Therefore the oxidation state of C in methane is $$-4$$ and that in carbon tetrachloride is $$+4$$.

What is the change in oxidation number of carbon in the following reaction?$$CH_4 (g) + 4Cl_2 (g)\longrightarrow CCl_4 (l) + 4HCl(g)$$

Correct option is B. $$-4$$ to $$+ 4$$$$\overset {-4} CH_4 (g) + 4Cl_2 (g)\longrightarrow \overset {+4} CCl_4 (l) + 4HCl(g)$$The oxidation state of $$H$$ and $$Cl$$ are +1 and -1 respectively. Therefore the oxidation state of C in methane is $$-4$$ and that in carbon tetrachloride is $$+4$$.

What is the change in oxidation number of carbon in the following reaction?
$$CH_4 (g) + 4Cl_2 (g)\longrightarrow CCl_4 (l) + 4HCl(g)$$

Correct option is B. $$-4$$ to $$+ 4$$
$$\overset {-4} CH_4 (g) + 4Cl_2 (g)\longrightarrow \overset {+4} CCl_4 (l) + 4HCl(g)$$
The oxidation state of $$H$$ and $$Cl$$ are +1 and -1 respectively. Therefore the oxidation state of C in methane is $$-4$$ and that in carbon tetrachloride is $$+4$$.