What is the correct electronic configuration of the central atom is $$K_4(Fe(CN)_6]$$ on crystal field theory?
Correct option is B. $$t_{2g}^6e^0_g$$
$$K_4[Fe(CN)_6]$$
Fe ground state $$[Ar]3d^64s^2$$
$$Fe^{2+}:3d^64s^0$$
So, B is the correct option.