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Question

What is the correct electronic configuration of the central atom is $$K_4(Fe(CN)_6]$$ on crystal field theory?

A
$$t_{2g}^6e^0_g$$
B
$$e^4t^{2}_2$$
C
$$e^3t_2^3$$
D
$$t_{2g}^4e_g^2$$
Solution
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Correct option is B. $$t_{2g}^6e^0_g$$
$$K_4[Fe(CN)_6]$$

Fe ground state $$[Ar]3d^64s^2$$

$$Fe^{2+}:3d^64s^0$$

So, B is the correct option.

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