What is the correct increasing order of solubility of the following salt?
NaHCO3,KHCO3,Mg(HCO3)2,Ca(HCO3)2
Ca(HCO3)2<NaHCO3<KHCO3<Mg(HCO3)2
KHCO3<Mg(HCO3)2<Ca(HCO3)2<NaHCO3
Mg(HCO3)2<Ca(HCO3)2<NaHCO3<KHCO3
NaHCO3<KHCO3<Mg(HCO3)2<Ca(HCO3)2
A
Ca(HCO3)2<NaHCO3<KHCO3<Mg(HCO3)2
B
KHCO3<Mg(HCO3)2<Ca(HCO3)2<NaHCO3
C
NaHCO3<KHCO3<Mg(HCO3)2<Ca(HCO3)2
D
Mg(HCO3)2<Ca(HCO3)2<NaHCO3<KHCO3
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Solution
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In the give metal bicarbonates, the anion (bicarbonate ion) is the same. Hence the solubility will depend on the size of cation. The size of Na+ ion is smaller than that of K+ ion. Hence sodium bicarbonate has high lattice energy and lower solubility than potassium bicarbonate. Similarly, the size of Mg+ ion is smaller than that of Ca+ ion. Hence magnesium bicarbonate has high lattice energy and lower solubility than calcium bicarbonate.
Hence, the correct option is (C)
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