What is the correct dimension of Newton-MLT-1-MLT-2-ML-2T-2-MLT-

Question

Toppr Admin · Accepted Answer

Force -mass-xD7-acceleration-xA0-Kgms-x2212-2-NewtonSince Newton is the unit of force-Hence- its dimensional analysis will be-xA0-MLT-x2212-2-The answer is option A-

What is the correct dimension of Newton?
$[M L T^{- 1}]$
$[M L T^{- 2}]$
$[M L^{2} T^{- 2}]$
$[M L T]$

Force $= m a s s \times a c c e l e r a t i o n$ $= K g m s^{- 2} = N e w t o n$
Since Newton is the unit of force.
Hence, its dimensional analysis will be $[M L T^{- 2}]$ .

The answer is option $A$ .

What is the correct dimension of Newton?[MLT−1][MLT−2][ML2T−2][MLT]

Force =mass×acceleration =Kgms−2=NewtonSince Newton is the unit of force.Hence, its dimensional analysis will be [MLT−2].The answer is option A.

What is the correct dimension of Newton?
$[M L T^{- 1}]$
$[M L T^{- 2}]$
$[M L^{2} T^{- 2}]$
$[M L T]$

Force $= m a s s \times a c c e l e r a t i o n$ $= K g m s^{- 2} = N e w t o n$
Since Newton is the unit of force.
Hence, its dimensional analysis will be $[M L T^{- 2}]$ .

The answer is option $A$ .