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# What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 Volt?12.27 ˚A1.227 ˚A0.1227 ˚A0.001227 ˚A

A
0.001227 ˚A
B
12.27 ˚A
C
1.227 ˚A
D
0.1227 ˚A
Solution
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#### Given : V=100 voltsde-Broglie wavelength of electron λ=h√2meV∴ λ=6.6×10−34√2(9.1×10−31)(1.6×10−19)(100)Or λ=6.6×10−345.4×10−10 m⟹ λ=1.227×10−10m=1.227 ˚A

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