What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 Volt?

Given :    $V=100$ volts

de-Broglie wavelength of electron     $\lambda =\frac{h}{\sqrt{2meV}}$

$\therefore$    $\lambda =\frac{6.6\times 10^{-34}}{\sqrt{2(9.1\times 10^{-31})(1.6\times 10^{-19})(100)}}$

Or     $\lambda =\frac{6.6\times 10^{-34}}{5.4\times 10^{-10}}$  m

$⟹$   $\lambda =1.227\times 10^{-10}m=1.227$  $\mathring{A}$