What is the electrical charge of the baryons with the quark compositions -a- bar u bar u bar d and -b- bar u bar d bar d -c- What are these baryons called-

Question

Toppr Admin · Accepted Answer

-a-bar u -bar u -bar d-160- -160- -160- -160-charge-Bigg-dfrac-2-3-e-Bigg-Bigg-dfrac-2-3-e-Bigg-Bigg-dfrac-1-3-e-Bigg-e-b-bar u -bar d -bar-160-d-160- -160- -160- -160-charge-Bigg-dfrac-2-3-e-Bigg-Bigg-dfrac-1-3-e-Bigg-Bigg-dfrac-1-3-e-Bigg-0-c- antiproton - antineutron

What is the electrical charge of the baryons with the quark compositions (a) $$\bar u \bar u \bar d$$ and (b) $$\bar u \bar d \bar d$$ (c) What are these baryons called?

(a)$$\bar u \bar u \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=-e$$
b)$$\bar u \bar d \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=0$$
(c) antiproton ; antineutron

What is the electrical charge of the baryons with the quark compositions (a) $$\bar u \bar u \bar d$$ and (b) $$\bar u \bar d \bar d$$ (c) What are these baryons called?

(a)$$\bar u \bar u \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=-e$$b)$$\bar u \bar d \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=0$$(c) antiproton ; antineutron

(a)$$\bar u \bar u \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=-e$$
b)$$\bar u \bar d \bar d$$: $$charge=\Bigg(-\dfrac{2}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)+\Bigg(\dfrac{1}{3}e\Bigg)=0$$
(c) antiproton ; antineutron